What is the eccentricity 10x^2+35y^2=5 ?

The eccentricity 10x^2+35y^2=5 is sqrt(5/7)

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eccentricity 10x^2+35y^2=5

eccentricity

\frac{5}{7}

Decimal

0.84515 \dots

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

10 x^{2} + 35 y^{2} = 5 :

Ellipse with center

(h, k) = (0, 0), a = \frac{1}{2}, b = \frac{1}{7}

= \frac{( \frac{1}{2} ) ^{2} - ( \frac{1}{7} ) ^{2}}{\frac{1}{2}}

\frac{( \frac{1}{2} ) ^{2} - ( \frac{1}{7} ) ^{2}}{\frac{1}{2}} = \frac{5}{7}

= \frac{5}{7}

What is the eccentricity 10x^2+35y^2=5 ?
The eccentricity 10x^2+35y^2=5 is sqrt(5/7)