What is the eccentricity (x^2)/9+(y^2)/5 =1 ?

The eccentricity (x^2)/9+(y^2)/5 =1 is 2/3

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eccentricity (x^2)/9+(y^2)/5 =1

eccentricity

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

\frac{2}{3}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 5

= \frac{3 ^{2} - ( 5 ) ^{2}}{3}

\frac{3 ^{2} - ( 5 ) ^{2}}{3} = \frac{2}{3}

= \frac{2}{3}

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

\frac{( x - 3 ) ^{2}}{2} + \frac{( y - 4 ) ^{2}}{4} = 1

What is the eccentricity (x^2)/9+(y^2)/5 =1 ?
The eccentricity (x^2)/9+(y^2)/5 =1 is 2/3