What is the axis (x^2)/9+(y^2)/(25)=1 ?

The axis (x^2)/9+(y^2)/(25)=1 is semi-major axis b=5, semi-minor axis a=3

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axis (x^2)/9+(y^2)/(25)=1

axis

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

semi - major axis b = 5, semi - minor axis a = 3

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 3

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

9 X^{2} + 4 Y^{2} = 36

25 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 9 ) ^{2}}{25} = 1

What is the axis (x^2)/9+(y^2)/(25)=1 ?
The axis (x^2)/9+(y^2)/(25)=1 is semi-major axis b=5, semi-minor axis a=3