What is the axis (x^2)/(36)+(y^2)/(16)=1 ?

The axis (x^2)/(36)+(y^2)/(16)=1 is semi-major axis a=6, semi-minor axis b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

axis (x^2)/(36)+(y^2)/(16)=1

axis

semi - major axis a = 6, semi - minor axis b = 4

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 4

What is the axis (x^2)/(36)+(y^2)/(16)=1 ?
The axis (x^2)/(36)+(y^2)/(16)=1 is semi-major axis a=6, semi-minor axis b=4