What is the axis x^2+y^2+10x-8y=-32 ?

The axis x^2+y^2+10x-8y=-32 is semi-major axis b=3, semi-minor axis a=3

Popular >

axis x^2+y^2+10x-8y=-32

axis

x^{2} + y^{2} + 10 x - 8 y = - 32

semi - major axis b = 3, semi - minor axis a = 3

Solution steps

x^{2} + y^{2} + 10 x - 8 y = - 32

Rewrite

x^{2} + y^{2} + 10 x - 8 y = - 32

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{3 ^{2}} + \frac{( y - 4 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, 4), a = 3, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 5, 4), b = 3, a = 3

\frac{( x + 5 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{4} = 1

2 x^{2} + 3 y^{2} = 4

\frac{( x - 4 ) ^{2}}{64} + \frac{( y - 2 ) ^{2}}{39} = 1

\frac{( x - 1 ) ^{2}}{13} + \frac{( y + 5 ) ^{2}}{12} = 1

10 x^{2} + 4 y^{2} + 2 x + 16 y = 144

What is the axis x^2+y^2+10x-8y=-32 ?
The axis x^2+y^2+10x-8y=-32 is semi-major axis b=3, semi-minor axis a=3