What is the axis ((x+8)^2)/(64)+((y-11)^2)/(36)=1 ?

The axis ((x+8)^2)/(64)+((y-11)^2)/(36)=1 is semi-major axis a=8, semi-minor axis b=6

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axis ((x+8)^2)/(64)+((y-11)^2)/(36)=1

axis

\frac{( x + 8 ) ^{2}}{64} + \frac{( y - 11 ) ^{2}}{36} = 1

semi - major axis a = 8, semi - minor axis b = 6

Solution steps

\frac{( x + 8 ) ^{2}}{64} + \frac{( y - 11 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 8 ) ^{2}}{64} + \frac{( y - 11 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 8 ) ) ^{2}}{8 ^{2}} + \frac{( y - 11 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 8, 11), a = 8, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 8, 11), a = 8, b = 6

5 x^{2} + 20 y^{2} = 50

\frac{x ^{2}}{3} + \frac{y ^{2}}{9} = 1

16 x^{2} + 25 y^{2} + 32 x - 150 y - 159 = 0

\frac{( x + 3 ) ^{2}}{25} + \frac{( y - 8 ) ^{2}}{16} = 1

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

What is the axis ((x+8)^2)/(64)+((y-11)^2)/(36)=1 ?
The axis ((x+8)^2)/(64)+((y-11)^2)/(36)=1 is semi-major axis a=8, semi-minor axis b=6