What is the axis x^2+(y^2)/(49)=1 ?

The axis x^2+(y^2)/(49)=1 is semi-major axis b=7, semi-minor axis a=1

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axis x^2+(y^2)/(49)=1

axis

x^{2} + \frac{y ^{2}}{49} = 1

semi - major axis b = 7, semi - minor axis a = 1

Solution steps

x^{2} + \frac{y ^{2}}{49} = 1

Rewrite

x^{2} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 1

\frac{( x + 6 ) ^{2}}{18} + \frac{( y + 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{16} + y^{2} = 1

3 x^{2} + 7 y^{2} - 12 x - 28 y + 19 = 0

x^{2} + y^{2} - 6 y = 0

\frac{x ^{2}}{20} + \frac{y ^{2}}{4} = 1

What is the axis x^2+(y^2)/(49)=1 ?
The axis x^2+(y^2)/(49)=1 is semi-major axis b=7, semi-minor axis a=1