What is the axis (x^2)/4+(y^2)/9 =4 ?

The axis (x^2)/4+(y^2)/9 =4 is semi-major axis b=6, semi-minor axis a=4

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axis (x^2)/4+(y^2)/9 =4

axis

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 4

semi - major axis b = 6, semi - minor axis a = 4

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 4

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 4

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 4

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

3 x^{2} + 3 y^{2} - 18 y = 0

4 x^{2} + y^{2} = 4

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

\frac{( x - 12 ) ^{2}}{100} + \frac{( y + 7 ) ^{2}}{36} = 1

What is the axis (x^2)/4+(y^2)/9 =4 ?
The axis (x^2)/4+(y^2)/9 =4 is semi-major axis b=6, semi-minor axis a=4