What is ((x+5)^2)/4-(y^2)/4 =1 ?

The solution to ((x+5)^2)/4-(y^2)/4 =1 is Hyperbola with (h,k)=(-5,0),a=2,b=2

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((x+5)^2)/4-(y^2)/4 =1

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

(h, k) = (- 5, 0), a = 2, b = 2

Solution steps

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 0), a = 2, b = 2

9 x^{2} - 4 y^{2} - 18 x - 16 y + 29 = 0

y^{2} - 25 x^{2} + 8 y - 9 = 0

x^{2} - y^{2} - 4 = 0

49 x^{2} - 36 y^{2} = 1764

(\frac{x ^{2}}{4}) - (\frac{y ^{2}}{9}) = 1

What is ((x+5)^2)/4-(y^2)/4 =1 ?
The solution to ((x+5)^2)/4-(y^2)/4 =1 is Hyperbola with (h,k)=(-5,0),a=2,b=2