What is ((x^2)/4)-((y^2)/9)=1 ?

The solution to ((x^2)/4)-((y^2)/9)=1 is Hyperbola with (h,k)=(0,0),a=2,b=3

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((x^2)/4)-((y^2)/9)=1

(\frac{x ^{2}}{4}) - (\frac{y ^{2}}{9}) = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 3

\frac{x ^{2}}{14} - \frac{y ^{2}}{30} = 1

3 x + 2 x^{2} - 3 y - 2 y^{2} + 1 = 0

4 y^{2} - x^{2} - 40 y + 8 x + 80 = 0

x^{2} - y^{2} = x

3 x^{2} - 6 y^{2} - 36 = 0

What is ((x^2)/4)-((y^2)/9)=1 ?
The solution to ((x^2)/4)-((y^2)/9)=1 is Hyperbola with (h,k)=(0,0),a=2,b=3