What is 4x^2+25y-8x+200y+304=0 ?

The solution to 4x^2+25y-8x+200y+304=0 is Parabola with (h,k)=(1,-4/3),p=-225/16

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4x^2+25y-8x+200y+304=0

4 x^{2} + 25 y - 8 x + 200 y + 304 = 0

(h, k) = (1, - \frac{4}{3}), p = - \frac{225}{16}

Solution steps

4 x^{2} + 25 y - 8 x + 200 y + 304 = 0

Rewrite

4 x^{2} + 25 y - 8 x + 200 y + 304 = 0

in the standard form

4 (- \frac{225}{16}) (y - (- \frac{4}{3})) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - \frac{4}{3}), p = - \frac{225}{16}

y^{1} = 8 y - 64 x^{2} + 6

(y - 6)^{2} = 32 (x + 1)

y^{2} - 4 y - 8 x + 44 = 0

y^{2} = - (x + 3)

5 x + y^{2} = 25

What is 4x^2+25y-8x+200y+304=0 ?
The solution to 4x^2+25y-8x+200y+304=0 is Parabola with (h,k)=(1,-4/3),p=-225/16