What is ((x+4)^2)/9-((y-1)^2)/(16)=1 ?

The solution to ((x+4)^2)/9-((y-1)^2)/(16)=1 is Hyperbola with (h,k)=(-4,1),a=3,b=4

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((x+4)^2)/9-((y-1)^2)/(16)=1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

(h, k) = (- 4, 1), a = 3, b = 4

Solution steps

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 1), a = 3, b = 4

x^{2} - 4 y^{2} \geq 4

x^{2} - y^{2} = 121

5 y^{2} + 24 y + 16 - 4 x^{2} = 0

- 12 x^{2} + 9 y^{2} + 24 x - 6 y + 9 = 0

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1

What is ((x+4)^2)/9-((y-1)^2)/(16)=1 ?
The solution to ((x+4)^2)/9-((y-1)^2)/(16)=1 is Hyperbola with (h,k)=(-4,1),a=3,b=4