What is (y^2)/4-(x^2)/(16)=1 ?

The solution to (y^2)/4-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=2,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y^2)/4-(x^2)/(16)=1

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1

(h, k) = (0, 0), a = 2, b = 4

Solution steps

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 4

- \frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{36} = 1

137 + 6 y = y^{2} - 24 x - x^{2}

\frac{y ^{2}}{25} - \frac{( x - 5 ) ^{2}}{16} = 1

4 x^{2} - y^{2} - 12 y + 36 = 0

9 x^{2} - 72 x - 4 y^{2} - 40 y + 44 = 36

What is (y^2)/4-(x^2)/(16)=1 ?
The solution to (y^2)/4-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=2,b=4