What is (y^2)/(25)-((x-5)^2)/(16)=1 ?

The solution to (y^2)/(25)-((x-5)^2)/(16)=1 is Hyperbola with (h,k)=(5,0),a=5,b=4

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(y^2)/(25)-((x-5)^2)/(16)=1

\frac{y ^{2}}{25} - \frac{( x - 5 ) ^{2}}{16} = 1

(h, k) = (5, 0), a = 5, b = 4

Solution steps

\frac{y ^{2}}{25} - \frac{( x - 5 ) ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{( x - 5 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 5 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 0), a = 5, b = 4

4 x^{2} - y^{2} - 12 y + 36 = 0

9 x^{2} - 72 x - 4 y^{2} - 40 y + 44 = 36

4 x^{2} + 24 x - 2 y^{2} + 36 = 36

\frac{( y - 3 ) ^{2}}{4} - \frac{( x + 1 ) ^{2}}{16} = 1

\frac{x ^{2}}{4 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

What is (y^2)/(25)-((x-5)^2)/(16)=1 ?
The solution to (y^2)/(25)-((x-5)^2)/(16)=1 is Hyperbola with (h,k)=(5,0),a=5,b=4