What is (x^2)/(4^2)-(y^2)/(3^2)=1 ?

The solution to (x^2)/(4^2)-(y^2)/(3^2)=1 is Hyperbola with (h,k)=(0,0),a=4,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/(4^2)-(y^2)/(3^2)=1

\frac{x ^{2}}{4 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{4 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

Rewrite

\frac{x ^{2}}{4 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 3

x^{2} + 6 = y^{2} + 6 x - 2 y

4 x^{2} - 24 x - y^{2} - 2 y = - 31

9 y^{2} - 4 x^{2} + 32 x - 36 y - 64 = 0

x^{2} + (2 - y^{2}) = 9

4 x^{2} - y^{2} - 16 x + 2 y + 11 = 0

What is (x^2)/(4^2)-(y^2)/(3^2)=1 ?
The solution to (x^2)/(4^2)-(y^2)/(3^2)=1 is Hyperbola with (h,k)=(0,0),a=4,b=3