What is x^2+(2-y^2)=9 ?

The solution to x^2+(2-y^2)=9 is Hyperbola with (h,k)=(0,0),a=sqrt(7),b=sqrt(7)

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x^2+(2-y^2)=9

x^{2} + (2 - y^{2}) = 9

(h, k) = (0, 0), a = 7, b = 7

Solution steps

x^{2} + (2 - y^{2}) = 9

Rewrite

x^{2} + (2 - y^{2}) = 9

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 7 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 7, b = 7

4 x^{2} - y^{2} - 16 x + 2 y + 11 = 0

(\frac{( y + 4 )}{9})^{2} - (\frac{( x - 3 )}{25})^{2} = 1

\frac{( x - 3 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{4} = 1

\frac{x ^{2}}{7} - \frac{y ^{2}}{6} = 1

25 x^{2} - y^{2} + 50 x + 6 y - 9 = 0

What is x^2+(2-y^2)=9 ?
The solution to x^2+(2-y^2)=9 is Hyperbola with (h,k)=(0,0),a=sqrt(7),b=sqrt(7)