What is -(y^2)/4+(z^2)/9 =1 ?

The solution to -(y^2)/4+(z^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=3,b=2

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-(y^2)/4+(z^2)/9 =1

- \frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

(h, k) = (0, 0), a = 3, b = 2

Solution steps

- \frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

Rewrite

- \frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( z - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 2

10 x^{2} - 64 y^{2} - 140 x + 768 y - 2454 = 0

y^{2} - 16 x^{2} = 1

\frac{( y - 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

x^{2} - y^{2} - 4 x - 6 y = 0

(3 x - 3)^{2} - (2 y - 4)^{2} = 68

What is -(y^2)/4+(z^2)/9 =1 ?
The solution to -(y^2)/4+(z^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=3,b=2