What is 16X^2-25Y^2+96X+544=0 ?

The solution to 16X^2-25Y^2+96X+544=0 is Hyperbola with (h,k)=(-3,0),a=4,b=5

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16X^2-25Y^2+96X+544=0

16 X^{2} - 25 Y^{2} + 96 X + 544 = 0

(h, k) = (- 3, 0), a = 4, b = 5

Solution steps

16 X^{2} - 25 Y^{2} + 96 X + 544 = 0

Rewrite

16 X^{2} - 25 Y^{2} + 96 X + 544 = 0

in the form of a standard hyperbola equation

\frac{( Y - 0 ) ^{2}}{4 ^{2}} - \frac{( X - ( - 3 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 0), a = 4, b = 5

7 x^{2} - 12 y^{2} - 14 x + 24 y - 28 = 0

(x - 2)^{2} - 4 (y + 2)^{2} = 4

2 x^{2} - y^{2} + 4 x + 4 y - 4 = 0

2 x^{2} - y^{2} + 12 x + 8 y + 6 = 0

36 + y^{2} - z^{2} = 4

What is 16X^2-25Y^2+96X+544=0 ?
The solution to 16X^2-25Y^2+96X+544=0 is Hyperbola with (h,k)=(-3,0),a=4,b=5