What is 36+y^2-z^2=4 ?

The solution to 36+y^2-z^2=4 is Hyperbola with (h,k)=(0,0),a=4sqrt(2),b=4sqrt(2)

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36+y^2-z^2=4

36 + y^{2} - z^{2} = 4

(h, k) = (0, 0), a = 42, b = 42

Solution steps

36 + y^{2} - z^{2} = 4

Rewrite

36 + y^{2} - z^{2} = 4

in the form of a standard hyperbola equation

\frac{( z - 0 ) ^{2}}{( 4 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 4 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 42, b = 42

y^{2} - 3 x^{2} = 3

9 x^{{2}} - 4 y^{{2}} = 36

y^{2} = 4 x^{2} + (- 2)

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 4

4 x^{2} + 24 x - 9 y^{2} + 54 y - 81 = 0

What is 36+y^2-z^2=4 ?
The solution to 36+y^2-z^2=4 is Hyperbola with (h,k)=(0,0),a=4sqrt(2),b=4sqrt(2)