What is 12x^2-4y^2=96 ?

The solution to 12x^2-4y^2=96 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2sqrt(6)

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12x^2-4y^2=96

12 x^{2} - 4 y^{2} = 96

(h, k) = (0, 0), a = 22, b = 26

Solution steps

12 x^{2} - 4 y^{2} = 96

Rewrite

12 x^{2} - 4 y^{2} = 96

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 6 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 22, b = 26

y^{2} - \frac{( x + 1 ) ^{2}}{4} = 1

x^{2} - y^{2} + 6 x = 16

\frac{( y - 6 ) ^{2}}{36} - \frac{( x + 1 ) ^{2}}{16} = 1

x^{2} - y^{2} = 2^{100}

x^{2} - y^{2} + x - y - 44 = 0

What is 12x^2-4y^2=96 ?
The solution to 12x^2-4y^2=96 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2sqrt(6)