What is x^2+y^2-8x^2+7=0 ?

The solution to x^2+y^2-8x^2+7=0 is Hyperbola with (h,k)=(0,0),a=1,b=sqrt(7)

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x^2+y^2-8x^2+7=0

x^{2} + y^{2} - 8 x^{2} + 7 = 0

(h, k) = (0, 0), a = 1, b = 7

Solution steps

x^{2} + y^{2} - 8 x^{2} + 7 = 0

Rewrite

x^{2} + y^{2} - 8 x^{2} + 7 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 7

16 x^{2} - 4 y^{2} = 64

(24 - x^{2}) + (4 - y)^{2} = \frac{x ^{2} + ( y + 3 ) ^{2}}{2 3 ^{2}}

(y - 1)^{2} - (x - 2)^{2} = 1

4 x^{2} - 9 y^{2} + 8 x - 36 y = 0

(\frac{x ^{2}}{1} + \frac{y ^{2}}{1 - 16}) (1 - 16) = 1 (1 - 16)

What is x^2+y^2-8x^2+7=0 ?
The solution to x^2+y^2-8x^2+7=0 is Hyperbola with (h,k)=(0,0),a=1,b=sqrt(7)