What is ((x^2)/1+(y^2)/(1-16))(1-16)=1(1-16) ?

The solution to ((x^2)/1+(y^2)/(1-16))(1-16)=1(1-16) is Hyperbola with (h,k)=(0,0),a=1,b=sqrt(15)

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((x^2)/1+(y^2)/(1-16))(1-16)=1(1-16)

(\frac{x ^{2}}{1} + \frac{y ^{2}}{1 - 16}) (1 - 16) = 1 (1 - 16)

(h, k) = (0, 0), a = 1, b = 15

Solution steps

(\frac{x ^{2}}{1} + \frac{y ^{2}}{1 - 16}) (1 - 16) = 1 \cdot (1 - 16)

Rewrite

(\frac{x ^{2}}{1} + \frac{y ^{2}}{1 - 16}) (1 - 16) = 1 (1 - 16)

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{( 15 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 15

\frac{x ^{2}}{25} - \frac{y ^{2}}{81} = 1

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{4} = 1

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

y^{2} \leq x^{2} + y

36 y^{2} = 4 x^{2} + 144

What is ((x^2)/1+(y^2)/(1-16))(1-16)=1(1-16) ?
The solution to ((x^2)/1+(y^2)/(1-16))(1-16)=1(1-16) is Hyperbola with (h,k)=(0,0),a=1,b=sqrt(15)