What is ((y-4)^2)/(36)-x^2=1 ?

The solution to ((y-4)^2)/(36)-x^2=1 is Hyperbola with (h,k)=(0,4),a=6,b=1

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((y-4)^2)/(36)-x^2=1

\frac{( y - 4 ) ^{2}}{36} - x^{2} = 1

(h, k) = (0, 4), a = 6, b = 1

Solution steps

\frac{( y - 4 ) ^{2}}{36} - x^{2} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{36} - x^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{6 ^{2}} - \frac{( x - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 4), a = 6, b = 1

x^{2} - y^{2} - 2 x + 4 y - 4 = 0

(x - y - 3) \cdot (x + y + 3) = 16

y^{2} - 3 y - 2 = x^{2}

\frac{( x + 1 ) ^{2}}{2} - \frac{( y - 2 ) ^{2}}{1} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

What is ((y-4)^2)/(36)-x^2=1 ?
The solution to ((y-4)^2)/(36)-x^2=1 is Hyperbola with (h,k)=(0,4),a=6,b=1