What is y^2=(x-4)(x+3) ?

The solution to y^2=(x-4)(x+3) is Hyperbola with (h,k)=(1/2 ,0),a= 7/2 ,b= 7/2

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y^2=(x-4)(x+3)

y^{2} = (x - 4) (x + 3)

(h, k) = (\frac{1}{2}, 0), a = \frac{7}{2}, b = \frac{7}{2}

Solution steps

y^{2} = (x - 4) (x + 3)

Rewrite

y^{2} - (x - 4) (x + 3) = 0

in the form of a standard hyperbola equation

\frac{( x - \frac{1}{2} ) ^{2}}{( \frac{7}{2} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{7}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (\frac{1}{2}, 0), a = \frac{7}{2}, b = \frac{7}{2}

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

24 = a^{2} - b^{2}

9 x^{2} - 25 y^{2} + 200 y = 625

f (x) (f (x)) = x^{2} + \frac{1}{4}

\frac{( y + 2 ) ^{2}}{30} - \frac{( x - 1 ) ^{2}}{8} = 1

What is y^2=(x-4)(x+3) ?
The solution to y^2=(x-4)(x+3) is Hyperbola with (h,k)=(1/2 ,0),a= 7/2 ,b= 7/2