What is f(x)(f(x))=x^2+1/4 ?

The solution to f(x)(f(x))=x^2+1/4 is Hyperbola with (h,k)=(0,0),a= 1/2 ,b= 1/2

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f(x)(f(x))=x^2+1/4

f (x) (f (x)) = x^{2} + \frac{1}{4}

(h, k) = (0, 0), a = \frac{1}{2}, b = \frac{1}{2}

Solution steps

yy = x^{2} + \frac{1}{4}

Rewrite

yy - x^{2} - \frac{1}{4} = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{2}, b = \frac{1}{2}

\frac{( y + 2 ) ^{2}}{30} - \frac{( x - 1 ) ^{2}}{8} = 1

- 2 x^{2} + y^{2} - 4 = 0

3 x^{2} - y^{2} + 30 x + 8 y = - 71

4 x^{2} - 4 y^{2} + 28 x - 8 y + 53 = 0

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

What is f(x)(f(x))=x^2+1/4 ?
The solution to f(x)(f(x))=x^2+1/4 is Hyperbola with (h,k)=(0,0),a= 1/2 ,b= 1/2