What is -x^2+4y^2=16 ?

The solution to -x^2+4y^2=16 is Hyperbola with (h,k)=(0,0),a=2,b=4

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-x^2+4y^2=16

- x^{2} + 4 y^{2} = 16

(h, k) = (0, 0), a = 2, b = 4

Solution steps

- x^{2} + 4 y^{2} = 16

Rewrite

- x^{2} + 4 y^{2} = 16

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 4

x^{2} - 10 x - 4 y^{2} - 8 y + 17 = 0

y^{2} - x^{2} - 9 = 0

9 x^{2} - y^{2} - 36 x - 2 y + 44 = 0

t^{2} = 27 + u^{2}

\frac{x ^{2}}{81} - \frac{y ^{2}}{4} = 1

What is -x^2+4y^2=16 ?
The solution to -x^2+4y^2=16 is Hyperbola with (h,k)=(0,0),a=2,b=4