What is ((y+1)^2}{36}-\frac{(x-4)^2)/4 =1 ?

The solution to ((y+1)^2}{36}-\frac{(x-4)^2)/4 =1 is Hyperbola with (h,k)=(4,-1),a=6,b=2

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((y+1)^2}{36}-\frac{(x-4)^2)/4 =1

\frac{( y + 1 ) ^{2}}{36} - \frac{( x - 4 ) ^{2}}{4} = 1

(h, k) = (4, - 1), a = 6, b = 2

Solution steps

\frac{( y + 1 ) ^{2}}{36} - \frac{( x - 4 ) ^{2}}{4} = 1

Rewrite

\frac{( y + 1 ) ^{2}}{36} - \frac{( x - 4 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 1 ) ) ^{2}}{6 ^{2}} - \frac{( x - 4 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, - 1), a = 6, b = 2

\frac{y ^{2}}{100} - \frac{x ^{2}}{64} = 1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

y^{2} = (x - 4)^{2} - 1

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

3 x^{2} - 3 y^{2} = 2 y

What is ((y+1)^2}{36}-\frac{(x-4)^2)/4 =1 ?
The solution to ((y+1)^2}{36}-\frac{(x-4)^2)/4 =1 is Hyperbola with (h,k)=(4,-1),a=6,b=2