What is ((x+5)^2)/(64)-((y-1)^2)/(36)=1 ?

The solution to ((x+5)^2)/(64)-((y-1)^2)/(36)=1 is Hyperbola with (h,k)=(-5,1),a=8,b=6

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((x+5)^2)/(64)-((y-1)^2)/(36)=1

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

(h, k) = (- 5, 1), a = 8, b = 6

Solution steps

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{8 ^{2}} - \frac{( y - 1 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 1), a = 8, b = 6

3 x^{2} - 3 y^{2} = 2 y

16 x^{2} - 9 y^{2} - 90 y - 369 = 0

y^{2} - z^{2} + 2 z - 4 = 0

9 x^{2} - 4 y^{2} - 54 x + 8 y - 113 = 0

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{9} = 1

What is ((x+5)^2)/(64)-((y-1)^2)/(36)=1 ?
The solution to ((x+5)^2)/(64)-((y-1)^2)/(36)=1 is Hyperbola with (h,k)=(-5,1),a=8,b=6