What is y^2-z^2+2z-4=0 ?

The solution to y^2-z^2+2z-4=0 is Hyperbola with (h,k)=(0,1),a=sqrt(3),b=sqrt(3)

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y^2-z^2+2z-4=0

y^{2} - z^{2} + 2 z - 4 = 0

(h, k) = (0, 1), a = 3, b = 3

Solution steps

y^{2} - z^{2} + 2 z - 4 = 0

Rewrite

y^{2} - z^{2} + 2 z - 4 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} - \frac{( z - 1 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 1), a = 3, b = 3

9 x^{2} - 4 y^{2} - 54 x + 8 y - 113 = 0

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{9} = 1

5 y^{2} + 30 y + 8 x - 79 - 4 x^{2} = 0

4 x^{2} - y^{2} - 24 x - 4 y + 16 = 0

\frac{( y - 1 ) ^{2}}{49} - \frac{( x - 2 ) ^{2}}{32} = 1

What is y^2-z^2+2z-4=0 ?
The solution to y^2-z^2+2z-4=0 is Hyperbola with (h,k)=(0,1),a=sqrt(3),b=sqrt(3)