What is 9(x-3)^2-4(y-1)^2=-36 ?

The solution to 9(x-3)^2-4(y-1)^2=-36 is Hyperbola with (h,k)=(3,1),a=3,b=2

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9(x-3)^2-4(y-1)^2=-36

9 (x - 3)^{2} - 4 (y - 1)^{2} = - 36

(h, k) = (3, 1), a = 3, b = 2

Solution steps

9 (x - 3)^{2} - 4 (y - 1)^{2} = - 36

Rewrite

9 (x - 3)^{2} - 4 (y - 1)^{2} = - 36

in the form of a standard hyperbola equation

\frac{( y - 1 ) ^{2}}{3 ^{2}} - \frac{( x - 3 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 1), a = 3, b = 2

x^{2} - y^{2} - 2 x - 2 y - 1 = 0

x, h (x)^{2} = 13 x^{2} - 6 x + 1

\frac{8 ( x ^{2} - \frac{1}{4} )}{\frac{9}{2}} - 9 y^{2} \frac{9}{2} = \frac{\frac{9}{2}}{\frac{9}{2}}

9 x^{2} - y^{2} = 144

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 5 ) ^{2}}{45} = 1

What is 9(x-3)^2-4(y-1)^2=-36 ?
The solution to 9(x-3)^2-4(y-1)^2=-36 is Hyperbola with (h,k)=(3,1),a=3,b=2