What is (x^2)/(12)-(y^2)/(16)=1 ?

The solution to (x^2)/(12)-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=4

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(x^2)/(12)-(y^2)/(16)=1

\frac{x ^{2}}{12} - \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 23, b = 4

Solution steps

\frac{x ^{2}}{12} - \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{12} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 3 ) ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 23, b = 4

244 - 98 y + 324 x - 49 y^{2} + 81 x^{2} = 0

3 a^{2} - 20 b^{2} - 100 = 0

x^{2} - 6 x + 8 y - y^{2} = 0

c^{2} = 5^{2} + a^{2}

9 x^{2} - 18 x - 4 y^{2} - 16 y = 43

What is (x^2)/(12)-(y^2)/(16)=1 ?
The solution to (x^2)/(12)-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=4