What is (y^2)/(25)-(x^2)/(49)=1 ?

The solution to (y^2)/(25)-(x^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=5,b=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y^2)/(25)-(x^2)/(49)=1

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

(h, k) = (0, 0), a = 5, b = 7

Solution steps

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 0 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 7

3 x^{2} - 2 y^{2} + 3 x - 4 y - 12 = 0

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{16} = 1

x^{2} - y^{2} = 96

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} - \frac{( y - k ) ^{2}}{( 2 ) ^{2}} = 1

3 y^{2} - x^{2} + 24 y - 2 x = 0

What is (y^2)/(25)-(x^2)/(49)=1 ?
The solution to (y^2)/(25)-(x^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=5,b=7