What is ((y+3)^2)/(64)-((x-2)^2)/(81)=1 ?

The solution to ((y+3)^2)/(64)-((x-2)^2)/(81)=1 is Hyperbola with (h,k)=(2,-3),a=8,b=9

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((y+3)^2)/(64)-((x-2)^2)/(81)=1

\frac{( y + 3 ) ^{2}}{64} - \frac{( x - 2 ) ^{2}}{81} = 1

(h, k) = (2, - 3), a = 8, b = 9

Solution steps

\frac{( y + 3 ) ^{2}}{64} - \frac{( x - 2 ) ^{2}}{81} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{64} - \frac{( x - 2 ) ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 3), a = 8, b = 9

x^{2} - y^{2} - 4 y = 1

x^{2} - 4 y^{2} - 10 x - 40 y - 100 = 0

3 x^{2} + 6 x = 0.3 y^{2} - 6 y

x^{2} - y^{2} = 45

\frac{x ^{2}}{16} - \frac{y ^{2}}{81} = 1

What is ((y+3)^2)/(64)-((x-2)^2)/(81)=1 ?
The solution to ((y+3)^2)/(64)-((x-2)^2)/(81)=1 is Hyperbola with (h,k)=(2,-3),a=8,b=9