What is ((x-1)^2)/(64)-((y-2)^2)/(32)=1 ?

The solution to ((x-1)^2)/(64)-((y-2)^2)/(32)=1 is Hyperbola with (h,k)=(1,2),a=8,b=4sqrt(2)

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((x-1)^2)/(64)-((y-2)^2)/(32)=1

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 2 ) ^{2}}{32} = 1

(h, k) = (1, 2), a = 8, b = 42

Solution steps

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 2 ) ^{2}}{32} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 2 ) ^{2}}{32} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{( 4 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 8, b = 42

- x^{2} + 9 y^{2} - 36 y + 27 = 0

(\frac{y - 4}{16})^{2} - (\frac{x - 6}{4})^{2} = 1

\frac{( x - 1 ) ^{2}}{49} - \frac{( y + 3 ) ^{2}}{9} = 1

(y - 3) (y + 1) - (2 x + 1) (x - 3) = 0

x^{2} - 3 y^{2} + 6 y + 6 = 0

What is ((x-1)^2)/(64)-((y-2)^2)/(32)=1 ?
The solution to ((x-1)^2)/(64)-((y-2)^2)/(32)=1 is Hyperbola with (h,k)=(1,2),a=8,b=4sqrt(2)