What is (x+y)(x-y)=1 ?

The solution to (x+y)(x-y)=1 is Hyperbola with (h,k)=(0,0),a=1,b=1

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(x+y)(x-y)=1

(x + y) (x - y) = 1

(h, k) = (0, 0), a = 1, b = 1

Solution steps

(x + y) (x - y) = 1

Rewrite

(x + y) (x - y) = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 1

\frac{( y + 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

18 x^{2} - 9 y^{2} - 96 x - 36 y - 36 = 0

\frac{x ^{2}}{14} - \frac{y ^{2}}{20} = 1

y^{2} - 2 x^{2} - 16 = 0

x^{2} = 280 0^{2} + y^{2} - 2 (2800) (y) cos (2 0^{\circ})

What is (x+y)(x-y)=1 ?
The solution to (x+y)(x-y)=1 is Hyperbola with (h,k)=(0,0),a=1,b=1