What is (3x-3)^2-(2y-4)^2=43+9+16 ?

The solution to (3x-3)^2-(2y-4)^2=43+9+16 is Hyperbola with (h,k)=(1,2),a=(2sqrt(17))/3 ,b=sqrt(17)

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(3x-3)^2-(2y-4)^2=43+9+16

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

(h, k) = (1, 2), a = \frac{2 17}{3}, b = 17

Solution steps

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

Rewrite

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{( \frac{2 17}{3} ) ^{2}} - \frac{( y - 2 ) ^{2}}{( 17 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = \frac{2 17}{3}, b = 17

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

25 x^{2} - 36 y^{2} - 200 x + 360 y - 1400 = 0

25 y^{2} - 9 x^{2} + 18 x - 50 y = 241

\frac{y ^{2}}{4} - \frac{x ^{2}}{6} = 1

- 4 x^{2} + y^{2} + 10 y - 11 = 0

What is (3x-3)^2-(2y-4)^2=43+9+16 ?
The solution to (3x-3)^2-(2y-4)^2=43+9+16 is Hyperbola with (h,k)=(1,2),a=(2sqrt(17))/3 ,b=sqrt(17)