What is -9y^2+9z^2=4 ?

The solution to -9y^2+9z^2=4 is Hyperbola with (h,k)=(0,0),a= 2/3 ,b= 2/3

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-9y^2+9z^2=4

- 9 y^{2} + 9 z^{2} = 4

(h, k) = (0, 0), a = \frac{2}{3}, b = \frac{2}{3}

Solution steps

- 9 y^{2} + 9 z^{2} = 4

Rewrite

- 9 y^{2} + 9 z^{2} = 4

in the form of a standard hyperbola equation

\frac{( z - 0 ) ^{2}}{( \frac{2}{3} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{2}{3} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{2}{3}, b = \frac{2}{3}

\frac{y ^{2}}{6} - \frac{x ^{2}}{3} = 1

y^{2} - 2 x^{2} - 4 x - 4 y = 8

x^{2} - y^{2} + 8 x + 24 y = 0

\frac{( x - 9 ) ^{2}}{16} - \frac{( y - 11 ) ^{2}}{9} = 1

- 9 x^{2} + z^{2} = 36

What is -9y^2+9z^2=4 ?
The solution to -9y^2+9z^2=4 is Hyperbola with (h,k)=(0,0),a= 2/3 ,b= 2/3