What is ((x-9)^2}{16}-\frac{(y-11)^2)/9 =1 ?

The solution to ((x-9)^2}{16}-\frac{(y-11)^2)/9 =1 is Hyperbola with (h,k)=(9,11),a=4,b=3

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((x-9)^2}{16}-\frac{(y-11)^2)/9 =1

\frac{( x - 9 ) ^{2}}{16} - \frac{( y - 11 ) ^{2}}{9} = 1

(h, k) = (9, 11), a = 4, b = 3

Solution steps

\frac{( x - 9 ) ^{2}}{16} - \frac{( y - 11 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 9 ) ^{2}}{16} - \frac{( y - 11 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 9 ) ^{2}}{4 ^{2}} - \frac{( y - 11 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (9, 11), a = 4, b = 3

- 9 x^{2} + z^{2} = 36

x^{2} - y^{2} = 19

4 x^{2} + 4 x + 1 - 2 y^{2} = 16

4 y^{2} - z^{2} = 4

x^{2} - y^{2} = 13

What is ((x-9)^2}{16}-\frac{(y-11)^2)/9 =1 ?
The solution to ((x-9)^2}{16}-\frac{(y-11)^2)/9 =1 is Hyperbola with (h,k)=(9,11),a=4,b=3