What is 4x^2+4x+1-2y^2=16 ?

The solution to 4x^2+4x+1-2y^2=16 is Hyperbola with (h,k)=(-1/2 ,0),a=2,b=2sqrt(2)

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4x^2+4x+1-2y^2=16

4 x^{2} + 4 x + 1 - 2 y^{2} = 16

(h, k) = (- \frac{1}{2}, 0), a = 2, b = 22

Solution steps

4 x^{2} + 4 x + 1 - 2 y^{2} = 16

Rewrite

4 x^{2} + 4 x + 1 - 2 y^{2} = 16

in the form of a standard hyperbola equation

\frac{( x - ( - \frac{1}{2} ) ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- \frac{1}{2}, 0), a = 2, b = 22

4 y^{2} - z^{2} = 4

x^{2} - y^{2} = 13

x^{2} - y^{2} = 14

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{8} = 1

- 9 x^{2} + y^{2} + 54 x - 117 = 0

What is 4x^2+4x+1-2y^2=16 ?
The solution to 4x^2+4x+1-2y^2=16 is Hyperbola with (h,k)=(-1/2 ,0),a=2,b=2sqrt(2)