What is ((x-1)^2)/4-((y+1)^2)/8 =1 ?

The solution to ((x-1)^2)/4-((y+1)^2)/8 =1 is Hyperbola with (h,k)=(1,-1),a=2,b=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/4-((y+1)^2)/8 =1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{8} = 1

(h, k) = (1, - 1), a = 2, b = 22

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{8} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{8} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 1), a = 2, b = 22

- 9 x^{2} + y^{2} + 54 x - 117 = 0

y^{2} = 6^{2} + x^{2} + 2 \cdot 6 \cdot x \cdot 0.5

y^{1} y = (x + 2) (x - 1)

3 (x - 1)^{2} = 6 + 2 (y + 1)^{2}

(x - 5)^{2} - (y - 4)^{2} = 25

What is ((x-1)^2)/4-((y+1)^2)/8 =1 ?
The solution to ((x-1)^2)/4-((y+1)^2)/8 =1 is Hyperbola with (h,k)=(1,-1),a=2,b=2sqrt(2)