What is ((x-6)^2)/4-((y+7)^2)/(36)=1 ?

The solution to ((x-6)^2)/4-((y+7)^2)/(36)=1 is Hyperbola with (h,k)=(6,-7),a=2,b=6

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((x-6)^2)/4-((y+7)^2)/(36)=1

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 7 ) ^{2}}{36} = 1

(h, k) = (6, - 7), a = 2, b = 6

Solution steps

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 7 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 7 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - 6 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 7 ) ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, - 7), a = 2, b = 6

\frac{( x - 3 ) ^{2}}{1} - \frac{( y - 2 ) ^{2}}{3} = 1

\frac{( y + 3 ) ^{2}}{( 64 )} - \frac{( x - 2 ) ^{(2)}}{( 84 )} = 1

5 x^{2} - 4 y^{2} - 20 x + 8 y - 4 = 0

\frac{( y - 1 ) ^{2}}{25} - \frac{( x + 2 ) ^{2}}{9} = 1

25 x^{2} - 4 y^{2} - 100 x - 16 y - 16 = 0

What is ((x-6)^2)/4-((y+7)^2)/(36)=1 ?
The solution to ((x-6)^2)/4-((y+7)^2)/(36)=1 is Hyperbola with (h,k)=(6,-7),a=2,b=6