What is ((y-5)^2)/(100)-((x+1)^2)/(25)=1 ?

The solution to ((y-5)^2)/(100)-((x+1)^2)/(25)=1 is Hyperbola with (h,k)=(-1,5),a=10,b=5

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((y-5)^2)/(100)-((x+1)^2)/(25)=1

\frac{( y - 5 ) ^{2}}{100} - \frac{( x + 1 ) ^{2}}{25} = 1

(h, k) = (- 1, 5), a = 10, b = 5

Solution steps

\frac{( y - 5 ) ^{2}}{100} - \frac{( x + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( y - 5 ) ^{2}}{100} - \frac{( x + 1 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - 5 ) ^{2}}{1 0 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 5), a = 10, b = 5

- (\frac{x - 3}{2})^{2} + (\frac{y - 2}{5})^{2} = 1

x^{2} - y^{2} = 2^{2}

x^{2} - 6 x - 9 y^{2} - 54 y - 81 = 0

\frac{( x - 4 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{4} = 1

9 x^{2} - 4 y^{2} + 90 x + 189 = 0

What is ((y-5)^2)/(100)-((x+1)^2)/(25)=1 ?
The solution to ((y-5)^2)/(100)-((x+1)^2)/(25)=1 is Hyperbola with (h,k)=(-1,5),a=10,b=5