What is ((x+4)^2)/(64)-((y+5)^2)/(81)=1 ?

The solution to ((x+4)^2)/(64)-((y+5)^2)/(81)=1 is Hyperbola with (h,k)=(-4,-5),a=8,b=9

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((x+4)^2)/(64)-((y+5)^2)/(81)=1

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

(h, k) = (- 4, - 5), a = 8, b = 9

Solution steps

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{8 ^{2}} - \frac{( y - ( - 5 ) ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 5), a = 8, b = 9

3 x^{(2)} - 12 y^{(2)} + 48 = 0

- 9 y^{2} + z^{2} = 36

3 x^{2} - y^{2} + 3 x + 4 y - 3 = 0

\frac{( x - 3 ) ^{2}}{10} - \frac{( y + 5 ) ^{2}}{9} = 4

x, 12 Y (x)^{2} - 15 x^{2} = 180

What is ((x+4)^2)/(64)-((y+5)^2)/(81)=1 ?
The solution to ((x+4)^2)/(64)-((y+5)^2)/(81)=1 is Hyperbola with (h,k)=(-4,-5),a=8,b=9