What is 3x^{(2)}-12y^{(2)}+48=0 ?

The solution to 3x^{(2)}-12y^{(2)}+48=0 is Hyperbola with (h,k)=(0,0),a=2,b=4

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3x^{(2)}-12y^{(2)}+48=0

3 x^{(2)} - 12 y^{(2)} + 48 = 0

(h, k) = (0, 0), a = 2, b = 4

Solution steps

3 x^{2} - 12 y^{2} + 48 = 0

Rewrite

3 x^{2} - 12 y^{2} + 48 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 4

- 9 y^{2} + z^{2} = 36

3 x^{2} - y^{2} + 3 x + 4 y - 3 = 0

\frac{( x - 3 ) ^{2}}{10} - \frac{( y + 5 ) ^{2}}{9} = 4

x, 12 Y (x)^{2} - 15 x^{2} = 180

9 x^{2} - 16 y^{2} - 90 x - 96 y - 63 = 0

What is 3x^{(2)}-12y^{(2)}+48=0 ?
The solution to 3x^{(2)}-12y^{(2)}+48=0 is Hyperbola with (h,k)=(0,0),a=2,b=4