What is ((x-2)^2)/4-((y-1)^2)/3 =1 ?

The solution to ((x-2)^2)/4-((y-1)^2)/3 =1 is Hyperbola with (h,k)=(2,1),a=2,b=sqrt(3)

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((x-2)^2)/4-((y-1)^2)/3 =1

\frac{( x - 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{3} = 1

(h, k) = (2, 1), a = 2, b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{3} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{3} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} - \frac{( y - 1 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 1), a = 2, b = 3

\frac{x ^{2} - y ^{2}}{11 \cdot 2} = 4

y^{2} - (x + 1)^{2} = 3

y \frac{y}{x} + 1 = x

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 6 ) ^{2}}{49} = 1

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{4} = 1

What is ((x-2)^2)/4-((y-1)^2)/3 =1 ?
The solution to ((x-2)^2)/4-((y-1)^2)/3 =1 is Hyperbola with (h,k)=(2,1),a=2,b=sqrt(3)