What is ((x-1)^2)/(25)-((y+6)^2)/(49)=1 ?

The solution to ((x-1)^2)/(25)-((y+6)^2)/(49)=1 is Hyperbola with (h,k)=(1,-6),a=5,b=7

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((x-1)^2)/(25)-((y+6)^2)/(49)=1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 6 ) ^{2}}{49} = 1

(h, k) = (1, - 6), a = 5, b = 7

Solution steps

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 6 ) ^{2}}{49} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 6 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{5 ^{2}} - \frac{( y - ( - 6 ) ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 6), a = 5, b = 7

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{4} = 1

36 x^{2} - 9 y^{2} - 324 = 0

x^{2} - y^{2} + 4 x = 0

x^{2} + 42 x + 441 = 72 y + y^{2}

\frac{( x - 5 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{25} = 1

What is ((x-1)^2)/(25)-((y+6)^2)/(49)=1 ?
The solution to ((x-1)^2)/(25)-((y+6)^2)/(49)=1 is Hyperbola with (h,k)=(1,-6),a=5,b=7