What is x^2-y^2+4x=0 ?

The solution to x^2-y^2+4x=0 is Hyperbola with (h,k)=(-2,0),a=2,b=2

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x^2-y^2+4x=0

x^{2} - y^{2} + 4 x = 0

(h, k) = (- 2, 0), a = 2, b = 2

Solution steps

x^{2} - y^{2} + 4 x = 0

Rewrite

x^{2} - y^{2} + 4 x = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 0), a = 2, b = 2

x^{2} + 42 x + 441 = 72 y + y^{2}

\frac{( x - 5 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{25} = 1

x, h (x)^{2} = (5)^{2} + (12)^{2} + (x)^{2}

4 x^{2} - y^{2} - 20 x - 10 y - 25 = 0

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0^{2}

What is x^2-y^2+4x=0 ?
The solution to x^2-y^2+4x=0 is Hyperbola with (h,k)=(-2,0),a=2,b=2