What is x^2-y^2+2x-5y+10=0 ?

The solution to x^2-y^2+2x-5y+10=0 is Hyperbola with (h,k)=(-1,-5/2),a=(sqrt(61))/2 ,b=(sqrt(61))/2

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x^2-y^2+2x-5y+10=0

x^{2} - y^{2} + 2 x - 5 y + 10 = 0

(h, k) = (- 1, - \frac{5}{2}), a = \frac{61}{2}, b = \frac{61}{2}

Solution steps

x^{2} - y^{2} + 2 x - 5 y + 10 = 0

Rewrite

x^{2} - y^{2} + 2 x - 5 y + 10 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - \frac{5}{2} ) ) ^{2}}{( \frac{61}{2} ) ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{( \frac{61}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - \frac{5}{2}), a = \frac{61}{2}, b = \frac{61}{2}

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What is x^2-y^2+2x-5y+10=0 ?
The solution to x^2-y^2+2x-5y+10=0 is Hyperbola with (h,k)=(-1,-5/2),a=(sqrt(61))/2 ,b=(sqrt(61))/2