What is ((x-4)^2)/(25)-((y+8)^2)/(49)=1 ?

The solution to ((x-4)^2)/(25)-((y+8)^2)/(49)=1 is Hyperbola with (h,k)=(4,-8),a=5,b=7

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((x-4)^2)/(25)-((y+8)^2)/(49)=1

\frac{( x - 4 ) ^{2}}{25} - \frac{( y + 8 ) ^{2}}{49} = 1

(h, k) = (4, - 8), a = 5, b = 7

Solution steps

\frac{( x - 4 ) ^{2}}{25} - \frac{( y + 8 ) ^{2}}{49} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{25} - \frac{( y + 8 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{5 ^{2}} - \frac{( y - ( - 8 ) ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, - 8), a = 5, b = 7

\frac{( x - 4 ) ^{2}}{9} - \frac{( y + 5 ) ^{2}}{16} = 1

(y - 4)^{2} - \frac{( x + 1 ) ^{2}}{16} = 1

144 y^{2} - 25 x^{2} = 3600

x^{2} - 25 y^{2} - 4 x + 75 y - 27 = 0

36 x^{2} - 4 y^{2} = 144

What is ((x-4)^2)/(25)-((y+8)^2)/(49)=1 ?
The solution to ((x-4)^2)/(25)-((y+8)^2)/(49)=1 is Hyperbola with (h,k)=(4,-8),a=5,b=7