What is x^2-y^2+2x+5=0 ?

The solution to x^2-y^2+2x+5=0 is Hyperbola with (h,k)=(-1,0),a=2,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-y^2+2x+5=0

x^{2} - y^{2} + 2 x + 5 = 0

(h, k) = (- 1, 0), a = 2, b = 2

Solution steps

x^{2} - y^{2} + 2 x + 5 = 0

Rewrite

x^{2} - y^{2} + 2 x + 5 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 0), a = 2, b = 2

x^{2} - y^{2} - 2 x - 8 y - 10 = 0

y^{2} = x^{2} + 361

4 x^{2} - y^{2} + 4 = 0

\frac{( x + 3 ) ^{2}}{49} - \frac{( y - 1 ) ^{2}}{48} = 1

5 x^{2} = 5 y^{2} + 45

What is x^2-y^2+2x+5=0 ?
The solution to x^2-y^2+2x+5=0 is Hyperbola with (h,k)=(-1,0),a=2,b=2